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7x^2-53x+8=0
a = 7; b = -53; c = +8;
Δ = b2-4ac
Δ = -532-4·7·8
Δ = 2585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-53)-\sqrt{2585}}{2*7}=\frac{53-\sqrt{2585}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-53)+\sqrt{2585}}{2*7}=\frac{53+\sqrt{2585}}{14} $
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